我们需要对类按照类中的某一个属性（或者多个属性）来对类的对象进行排序，有两种方法可以实现，一种方法是类实现Comparable<T>接口，然后调用Collections.sort(List)方法进行排序，另一种方法是类不实现Comparable<T>接口，而在排序时使用Collections.sort(List, Comparator<T>)方法，并实现其中的Comparator<T>接口。
先创建一个简单的学生类：
public class Student {
private String name;
private int age;
public Student() {}
public Student(String name, int age) {
this.name = name;
this.age = age;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
}
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1、通过类实现Comparable<T>接口进行排序
public class Student implements Comparable<Student>{
private String name;
private int age;
public Student() {}
public Student(String name, int age) {
this.name = name;
this.age = age;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
/**
* 将对象按姓名字典序升序排序
* @param o
* @return
*/
@Override
public int compareTo(Student o) {
return this.name.compareTo(o.getName());
}
@Override
public String toString() {
return "Student{" +
"name='" + name + '\'' +
", age=" + age +
'}';
}
}
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2、通过在Collections.sort()方法中实现Comparable<T>接口来实现排序
public class Client {
public static void main(String[] args){
List<Student> students = new ArrayList<>();
students.add(new Student("a", 18));
students.add(new Student("c", 19));
students.add(new Student("b", 20));
Collections.sort(students, new Comparator<Student>() {
@Override
public int compare(Student o1, Student o2) {
return o1.getAge()>o2.getAge()? -1:(o1.getAge()==o2.getAge()? 0:1);
}
});
for(Student student:students){
System.out.println(student.toString());
}
}
}
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原文链接：https://www.php.cn/java-article-438306.html
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